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12x^2=0.5
We move all terms to the left:
12x^2-(0.5)=0
We add all the numbers together, and all the variables
12x^2-0.5=0
a = 12; b = 0; c = -0.5;
Δ = b2-4ac
Δ = 02-4·12·(-0.5)
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{6}}{2*12}=\frac{0-2\sqrt{6}}{24} =-\frac{2\sqrt{6}}{24} =-\frac{\sqrt{6}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{6}}{2*12}=\frac{0+2\sqrt{6}}{24} =\frac{2\sqrt{6}}{24} =\frac{\sqrt{6}}{12} $
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